Média

Questão 1

StM

X ̅=(14,77+11,71+10,89+12,55+13,77+15,77+11,76+5,33+10,21+12,55+13,21+15,45)/12=147,94/12=12,33

P_(o_1 ) P_(o_2 )

5,33;10,21;10,89;11,71;11,76;12,55;12,55;13,21;13,77;14,77;15,45;15,77

Mo

P_(o_1 )=12/2=6

P_(o_2 )=12/2+1=7

Md=(12,55+12,55)/2=25,1/2=12,55

StM=X ̅=12,33;Md=12,55;Mo=12,55

S=√((5,95+0,38+2,07+0,04+2,07+11,83+0,32+49,00+4,49+0,04+0,77+9,73)/11)=86,69/11

S=√7,88

S= 2,80

CV=S/X ̅ =2,80/12,33=0,23 ou 23%

IA=(3*(X ̅-Md))/S

IA=(3*(12,33-12,55))/2,80=(3*(-0,22))/2,80=(-0,66)/2,80=-0,23

StM=S=2,80;CV=0,23 ou 23%;IA=-0,23

Limite inferior do intervalo

12,33-2*2,80=12,33-5,6=6,73

Limite superior do intervalo

12,33+2*2,80=12,33+5,60=17,93

StA

X ̅=(23,65+22,65+21,22+23,99+25,88+26,77+23,66+6,77+12,32+14,66+21,66+26,88)/12

X ̅=250,11/12=20,84

P_(o_1 ) P_(o_2 )

6,77;12,32;14,66;21,22;21,66;22,65;23,65;23,66;23,99;25,88;26,77;26,88

Md=(22,65+23,65)/2=46,30/2=23,15

StA=X ̅=20,84;Md=23,15

S=√((7,90+3,28+0,14+9,92+25,40+35,16+7,95+197.96+72,59+38,19+0,67+36,48)/11)

S=√(435,64/11)

S=√39,60=6,29

CV=6,29/20,84=0,30 ou 30%

IA=(3*(20,84-23,15))/6,29

IA=(3*(-2,31))/6,29

IA=(-6,93)/6,29=-1,10

StA=S=6,29;CV=0,30 ou 30%;IA=-1,10

Limite inferior do intervalo

20,84-2*6,29=20,84-12,58=8,26

Limite superior do intervalo

20,84+2*6,29=20,84+12,58=33,42

Questão 2

Sim existem picos, no setor metalurgico