A Lista de Atividades

ALEX PESSOA PIMENTEL 3110494

Resposta. 1

        =        5[pic 1]

1000

---

→ 5 ∗ 10−³

• 𝑋𝑐 =        1[pic 2][pic 3]

W∗C

---

1

[pic 4]

5000∗(5∗10−3)

---

∗ 1000 = 40Ω 𝗅 90

        = 32[pic 5]

1000

---

→ 0,032

• 𝑋𝑙 = w ∗ l → 5000 ∗ 0,032 = 160 Ω 𝗅 − 90

• 𝐼𝑓 𝑝𝑖𝑐𝑜 = 750 → 18,75 A[pic 6]

40

• 𝐼𝑓 𝑝𝑖𝑐𝑜 𝑎 𝑝𝑖𝑐𝑜 = 2 ∗ 18,75 → 37,5 A

• 𝐼𝑓𝑟𝑚𝑠 = 18,75 → 13,25 A[pic 7]

√

Resposta. 2

        = 20[pic 8]

2∗π

---

→ 3.18

• 𝑋𝑙 = 2 ∗ π ∗ 3.18 ∗ 0,5 → 10

• 𝑍𝑡 = 10 KΩ 𝗅 0,06

• 𝑉1 = 10 𝐾 𝗅 0,06 * √2 𝗅 15[pic 9]
• 𝑉𝑡 = 14,142 𝗅 −14,94

Resposta. 3

        = 𝐴[pic 10]

√2

---

→ 70,7 = 50 𝗅 0 V

√2[pic 11]

• 𝑍𝑡 = Zr + Zl + Zc → 3 𝗅 0 + 7 𝗅 90 + 3 𝗅 −90
• → 3  𝗅 0 +  4  𝗅 0 → POL ( 3 , 4 ) → 5
• θ = Tg−1→ 4 → 1,333 + ( 𝑆ℎ𝑖𝑓𝑡 + 𝑡𝑎𝑛−1) = 53,13°[pic 12]

5

        = 5 𝗅 53,13°

• 𝐼 = 𝑉[pic 13]

𝑍𝑡

---

→   50 𝗅0

5 𝗅53,13[pic 14]

---

= 10 𝗅 −53,13

• 𝑉𝑟 = I ∗ Zr → 10 𝗅 −53,13 ∗ 3 𝗅 0 = 30 𝗅 −53,13

• 𝑉𝑙 = I ∗ Z𝑙 → 10 𝗅 −53,13 ∗ 7 𝗅 90 = 70 𝗅 36,87

• 𝑉𝑐 = I ∗ Zc → 10 𝗅 −53,13 ∗ 3 𝗅 −90 = 30 𝗅 −143,13

Resposta. 4

        =        1[pic 15]

1,67

        =        1[pic 16]

1,25

---

→ 0,6

→ 0,8

• 𝑌𝑡 = Yr + Yc → 0,6 𝗅 0 + 0,8 𝗅 90 → POL ( 0.6 , 0.8 ) → 1
• θ = Tg−1→ 0.8 → 1,333 + ( 𝑆ℎ𝑖𝑓𝑡 + 𝑡𝑎𝑛−1) = 53,13°[pic 17]

0.6

        = 1 𝗅 53,13°

• 𝐼 = 10 𝗅 0

• 𝑉 = Zt ∗ I → 1 𝗅 53,13 ∗ 10 𝗅 0 = 10 𝗅 −53,13

• 𝐼𝑟 = V ∗ Yr → 10 𝗅 −53,13 ∗ 0.6 𝗅 0 = 6 𝗅 −53,13

• 𝐼𝑐 = I ∗ Zc → 10 𝗅 −53,13 ∗ 0.8 𝗅 90 = 8 𝗅 36,87

Resposta. 5

 P/ 1kHz

• Xc =        1[pic 18]

2∗ 𝜋∗𝑓1∗𝐶

---

→        1

2∗ 𝜋∗1000∗0,47[pic 19]

---

→ 3.38 𝐾Ω

[pic 20]

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