Trabalho Física
Por: Stephany Costa • 7/11/2019 • Pesquisas Acadêmicas • 1.170 Palavras (5 Páginas) • 118 Visualizações
PRIMEIRO CAPÍTULO
A) S = {(1;C), (2,C), (3,C), (4,C), (5,C), (6,C),(1,K),(2,K),(3,K),(4,K),(5,K),(6,K)
B) A= {(2,K),(4,K),(6,K)}
B= {(1,C),(3,C),(5,C)}
C={(3,C),(3,K),(6,C),(6,K)}
C) 1) B = {(2,C),(4,C),(6,C),(1,K),(2,K),(3,K),(4,K),(5,K),(6,K)}
(II) AUB= {(2,K),(4,K),(6,K),(1,C),(3,C),(5,C)}
(III)B ∩C={(3,5)}
(IV) AUB ={(1,K),(3,K),(5,K),(2,C),(4,C),(6,C)}
D) Exclusivos
2-
A) P(A)= ½ B) P(B)=3/4 C)P(A∩B)=0
D) P(AUB) =1/2+1/4=3/4 E) P (A∩B)=1
3-
A) P(AUB) = 1/2+ 1/3-1/4= 6+4-3/12=7/12
B) P(AUB) = 1-P(AUB)=1-1/4=3/4
C) P (A∩B) 1 – 7/12=5/12
4-
- P= 3/6=1/2 B) P= 4/52=1/13
- C )P=7/8
- D) 1-(1/2)N = 1- 1/2N = 2N-1/2N
- E) 13/52.12/51=1/17
- F) 12/52.13/51=169/2652=12/204
5-
A)10/50=1/5 B)5/50=1/10 C)15/50=3/10 D)12/50=6/25
6-
P = 16/52 = 8/26 =4/13
12-
P2O =4/12.3/11=12/132 PHO= 5/12.4/11.3/10=12/132
P3O=3/12.2/11=6/132 PT=12/132+6/132+12/132=5/22
SEGUNDO CAPÍTULO
A)
W | -5 | -4 | -3 | -2 | -1 | 0 | 1 | 2 | 3 | 4 | 5 |
P(W) | 1/36 | 2/36 | 3/36 | 4/36 | 5/35 | 6/36 | 5/36 | 4/36 | 3/36 | 2/36 | 1/36 |
[pic 1]
-5 -4 -3 -2 -1 0 1 2 3 4 5 6
II.
A | 2 | 4 | 6 | 8 | 9 | 10 | 12 |
P(W) | 1/6 | 1/6 | 1/6 | 1/6 | 1/6 | 1/6 | 1/6 |
P(A)
1/6
[pic 2]
III.
Z | 1 | 2 | 3 | 4 | 5 | 6 | 8 | 9 | 10 | 12 | 15 | 16 |
PW | 1/36 | 2/36 | 2/36 | 3/36 | 2/36 | 4/36 | 2/36 | 1/36 | 2/36 | 4/36 | 2/36 | 1/36 |
IV.
B | 1 | 2 | 3 | 4 | 5 | 6 |
P(B) | 1/36 | 3/36 | 5/36 | 7/36 | 9/36 | 11/36 |
B.
W < +5 F=0
+5 ≤ W <-4 F=1/36
-4 ≤ W <-3 F=3/36
-3 ≤W<-2 F=6/36
-2 ≤W<-1 F=10/36
-1 ≤W<0 F=15
0 ≤W<1 F=26
2 ≤W<2 F=26/36
3 ≤W<3 F=30/36
4 ≤W<5F=35/36
5 ≤W F=1
12.
Z <1<2 F=1/36
1 ≤Z<3 F=3/36
2 ≤Z<4 F=5/36
3 ≤Z<5 F=8/36
4 ≤Z<6 F=10/36
5 ≤Z<8 F=14/36
6 ≤Z<9 F=16/36
8 ≤Z<10 F=17/36
9 ≤Z<12 F=19/36
10 ≤Z<15 F=23/36
12 ≤Z<16 F=25/36
15 ≤Z<18 F=26/36
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