Estudos Disciplinares 2° Periodo Engenharia
Por: Geovana Silva Biondo • 4/11/2015 • Pesquisas Acadêmicas • 300 Palavras (2 Páginas) • 571 Visualizações
13)
^ = ESCALAR
FAB = I x L1 ^ B
FAB = 4 x 0,3 k ^ 0,5 j
FAB = 1,2 k ^ 0,5 j
FAB = - 0,6 i N
FBC = I x L2 ^ B
FBC = 4 x 0,2 j ^ 0,5 j
FBC = 0
21)
Eaq1 = L x Q1 / r²
Eaq1 = 9 x 10 ^ 9 x - 12,5 x 10 ^ (-6) / 0,15² = -5x10^6 V/m
Eaq2 = L x Q1 / r²
Eaq2 = 9 x 10 ^ 9 x -25 x 10 ^ (-6) / 0,10² = -2,25x10^7 V/m
Ea = Eaq1 - Eaq2 = -5x10^6 - (-2,25x10^7) = 1,75 x 10 ^ 7 i V/m
Ebq1 = L x Q1 / r²
Ebq1 = 9 x 10 ^ 9 x -12,5 x 10 ^ (-6) / 0,10² = -1,125x10^7 V/m
Ebq2 = L x Q1 / r²
Ebq2 = 9 x 10 ^ 9 x -25 x 10 ^ (-6) / 0,35² = -1,84x10^6 V/m
Eb = Ebq1 + Ebq2 = -1,125x10^7 - (-1,84x10^6) = 1,309 x 10 ^ 7 i V/m
F = q x E
Fa = q x Ea
Fa = 4 x 10 ^ (-3) x 1,75 x 10^7 = 7 x 10 ^ 4 i N
Fb = q x Eb
Fb = 4x10^(-3) x 1,309x10^7 = 5,236 x 10 ^ 4 i N
28)
VP = L x (qa/"AP" + qb/"BP" + qc/"CP")
VP = 9x10^9 x (4x10^(-6)/11 + (-2x10^(-6))/10 + 6x10^(-6)/45^(1/2))
VP = 9x10^9 x (3,64x10^(-7) - 2x10^(-7) + 8,94x10^(-7))
VP = 9x10^9 x 1,0584x10^(-6)
VP = 9,522x10^3 V
V0 = L x (qa/"A0" + qb/"B0" + qc/"C0")
V0 = 9x10^9 x (4x10^(-6)/5 + (-2x10^(-6))/8 + 6x10^(-6)/3)
V0 = 9x10^9 x (8x10^(-7) - 2,5x10^(-7) + 2x10^(-6))
V0 = 9x10^9 x 2,55x10^(-6)
V0 = 2,295x10^4 V
P0 = q x (VP - V0)[pic 1]
P0 = -0,5x10^(-6) x (9,522x10^3 -2,295x10^4)[pic 2]
P0 = 6,714x10^(-3) J [pic 3]
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