Bolsa

Since the downward component of the net field, when bead 1 is on the +y axis, is of

largest magnitude, then bead 1 must be a positive charge (so that its field is in the same

direction as that of bead 2, in that situation). Comparing the values of Ey at 0° and at 90°

we see that the absolute values of the charges on beads 1 and 2 must be in the ratio of 5 to

4. This checks with the 180° value from the Ex graph, which further confirms our belief

that bead 1 is positively charged. In fact, the 180° value from the Ex graph allows us to

solve for its charge (using Eq. 22-3):

q1 = 4πεor²E = 4π( 8.854 × 10−12 C2

Since the downward component of the net field, when bead 1 is on the +y axis, is of

largest magnitude, then bead 1 must be a positive charge (so that its field is in the same

direction as that of bead 2, in that situation). Comparing the values of Ey at 0° and at 90°

we see that the absolute values of the charges on beads 1 and 2 must be in the ratio of 5 to

4. This checks with the 180° value from the Ex graph, which further confirms our belief

that bead 1 is positively charged. In fact, the 180° value from the Ex graph allows us to

solve for its charge (using Eq. 22-3):

q1 = 4πεor²E = 4π( 8.854 × 10−12 C2