Fisica
Exam: Fisica. Pesquise 862.000+ trabalhos acadêmicosPor: aureliotnb • 30/9/2014 • Exam • 429 Palavras (2 Páginas) • 165 Visualizações
Exercícios física resposta
1R
(6.37 × 106 m)(10−3 km m) = 6.37 × 103 km,
A = 2π R = 2xπ 6.37 x 106km = 40023
B= 4π R2 = 4π 6.37 x 103 km 2 = 509.90
C = 44π/3*r3= 4π/3 6.37 ×103 km 3 = 1.082
3 R
a 1km x 103 m = (103 m)(106 μ m /m) = 100000000 μm
b γd/1μ = 9.144μm
4R
A = 0.80 x1p/2.54x6paica/1p =1.889picas
B = 0,80x1/2.54 x 6/1 x12/1=22.677
5R
10 furlong; 201.168m;
(201.168m).1vara/5.0292m = 40 varas
1.0 furlong 201,168m =
(201.168m)x1/20.117m = 10 cadeias
4.0 furblongs
(4.0) 40/1varas = 160 varas
4.0 flurlong
(4.0) 10/1 =40 cadeias
6R
a
1cah =12fan1 fan = 1/2 cah = 0,0833 = 8,33x^(-2) cah
1 cah=48 cuatrilha1/48 = 0,0208=2,08x〖10〗^(-2) cah
1 cah 144 almu 1/144 cah=0,0833=6,94x〖10〗^(-3)
1 cah =288 medio 1/288 cah=0,0833=3,47x〖10〗^(-3)
b
1 fan 4cuartill 1/4 fan=0,25=2,50x〖10〗^(-2)
1 fan = 12 almu1/12 fane-0,0833=8,33〖10〗^(-2)
1 fan=24 medio=1/4 fan=0,0417=4.17x〖10〗^(-2)
c
1fan=55,501 dm ^3
1dm^3=1000cm^3
7/12 fan (55,501cm3)=3,24x〖10〗^4 cm3
7R
1 acre pes=(43,560km2)ft=23,560ft3
(26km2)(91/6ft)=(26km2)(3281ftkm) ^(2 ) (1/6ft)
4.66x〖10〗^7 ft3
(4.66x〖10〗^7 ft^3)/(4.3560x〖10〗^4 ft^3 )/ acreft =1.1x〖10〗^3 acre ft
8R
50.0s (258/212s)=60.8w
50.0s(156z/180s)=43.3z
9R
v=π/2 r^2 z
((2000km)(〖10〗^3/1km)((〖10〗^2 cm)/1m)=2000x〖10〗^3 cm
3000m=((〖10〗^2 cm)/1m)=3000x〖10〗^2 cm
π/2 (2000x〖10〗^5 cm)2 (3000x〖10〗^2 cm) 1 .9x〖10〗^22 cm3
10R
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