Atps fisica II
Por: dalison • 16/6/2015 • Pesquisas Acadêmicas • 578 Palavras (3 Páginas) • 301 Visualizações
[pic 1]
V0 = 20m/s a = -5m/s2
- v = vo + a.t 0 = 20 – ( 5 . t ) -5t = -20 (-1) t = 4s
- V2 = V02 + 2ad 02 = 202 + 2 . (-5) . d d = 400/10
[pic 2]
Va= 2m/s Vb= 3m/s D= 5m T=?
V2 = V02 + 2ad 32 = 22 + 2 . A . 5 10a = 9 – 4 a = 0,5m/s2
v = vo + a.t 3 = 2 + 0,5 . t 0,5t = 1 t = 2s
[pic 3]
T = 40s A = 3m/s2 V0 = 4m/s D = ?
v = vo + a.t v = 4 + 3 . 40 v = 124 m/s
V2 = V02 + 2ad 1242 = 42 + 2 . 3 . d 6d = 15376 – 16 d= 15360/6 d = 2560m[pic 4]
- S(t) = 4,9 . t2 t = 2
S(2) = 4,9 . 22 S(2) = 19,6 d= 19,6m
- b) S(t) = 4,9 . t2 t = 2
S(2) = 4,9 . 22 S(2) = 19,6m v= 19,6 m/s
[pic 5]
- d(t) = t3- 3t2 + 6t + 5 t = 3s
d(3) = (33) – (3 . 32) + (6 . 3) + 5 d(3) = 23m
- d(t) = t3- 3t2 + 6t + 5 t = 5s
d(3) = (53) – (3 . 52) + (6 . 5) + 5 d(3) = 85m
- d(t) = t3- 3t2 + 6t + 5 t = 5s v’(t) = 3t2- 6t + 6 t = 4s
V’(4) = 3 . 42 – 6 . 4 + V´(4) = 85m
- d(t) = t3- 3t2 + 6t + 5 t = 5s v’(t) = 3t2- 6t + 6 t = 5s
V’(5) = (3 .( 52)) – ( 6 . 5) + 6 V´(4) = 51m
- v’(t) = 3t2- 6t + 6 t = 5s a=v´´(t) = 6t – 6 t= 3s
a=v´´(3) = (6 . 3) – 6 a = 12m/s2
- v’(t) = 3t2- 6t + 6 t = 5s a=v´´(t) = 6t – 6 t= 6s
a=v´´(6) = (6 . 6) – 6 a = 30m/s2
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