Eds 5 semestre Engenharia Mecânica
Por: Cintia Carolina Paula • 30/7/2015 • Trabalho acadêmico • 1.022 Palavras (5 Páginas) • 1.096 Visualizações
ED 1 - Alternativa E
EFV = 0
– VA – 10 + VB – 40=0
VB = VA + 50
VB = RA cos (30º) + 50 (Equação I)
EFH = 0
HA + 10 – HB + 15 = 0
HB = HA + 25 (Equação II)
MA = 0
– 5 + 2 * HB + 2 * VB – 40 * 30 – 15 * 2 = 0
2HB + 2VB – 155=0
2 * (RA sen (30º) +25) + 2 * (RA cos (30º) + 50) = 155
RA + 50 + 1,73 * RA + 100 = 155
2,73 * RA = 155-150
RA = 5 / 2,73
RA = 1,83 kN
Em I: VB = 51,58 kN
Em II: HB = 25,92 kN
ED 2 - Alternativa A
EFH = 0
RH = -5 kN
EFV = 0
RV = 4 kN
EM =0
MR+4-4*1+5*2 = 0
MR = -10 kNm
S1
N = -5 Kn
V = -2*1,2 V = -2,4 Kn
M = -2,4*0,6 M= 1,44 kNm (TC)
S2
N = -5 Kn
V = -2,4 + ( -2* 0,8) V = - 4 kN
M = - 1,44 – 4 * 2,8 M= 12 kNm (TC)
S3
N = -4kN
V = 5kN
M = -4 * 3 + 4 M= 8 kNm (TD)
S4
N = 5kN
V = 4kN
M = -8 + 10 M = 2 kNm (TC)
ED 3 – ALT C
M5,6=0
V1x2-5+40-10x2+10x2=0 => v1= -17,5 KN
S1:
FV=0 FH=0 M=0
-N-17,5=0=>N=-17,5 KN V+10=0 => V=-10 KN M=0
S2:
FV=0 FH=0 M=0
-17,5-N=0 =>N=-17,5 KN V+10=0 => V=-10 KN 10x1,2=12 KN.m
S3:
FV=0 FH=0 M=0
-N-17,5=0 => N=-17,5 KN 10-V=0 => V=-10 KN 10x2=20 KN.m
S4:
FV=0 FH=0 M=0
V-17,5=0 => V=17,5 KN N+10=0 => N=-10 KN 10x2-5=15KN.m
S5:
FV=0 FH=0 M=0
V-40-17,5=0 =>V=-12,5 KN N+10=0 => N=-10 KN 40-5+17,5=20KN.m
ED 4 – ALT B
F= 20 * 2 = 40 KN
X = 2/2 = 1m
MA = 0
(10*4) – (2*A) + (40 *1) – (10*2) = 0
A= 30kN
ΣFy = 0
A + By -10-10- 40 = 0
By = 30 kN
(S1)
ΣFx = 0
N = 0
ΣFy = 0
-10 – V = 0 => V = -10
ΣM. = 0
M = 0
(S2)
ΣFx = 0
N = 0
ΣFy = 0
-10 –V = 0 => V=-10
ΣM. = 0
M – (10*2) = 0 => M = 20
(S3)
ΣFx = 0
N =0
ΣFy = 0
-V – 10 + 30 = 0 => V =20
ΣM. = 0
M – (10*2) = 0 => M=20
(S4)
ΣFx = 0
N = 0
ΣFy = 0
V=0
ΣM. = 0
M = (40*1) – 30 = 10
(S5)
ΣFx = 0
N = 0
ΣFy = 0
V – 10 + 30 -30 = 0
V = 10
ΣM. = 0
M= 10*2 = 20
(S6)
ΣFx = 0
N = 0
ΣFy = 0
-V = -10 => V=10
ΣM. = 0
M=0
ED 5 – ALT A
Somatória de forças na horizontal:
10+15-HB=0
HB=25KN
Somatória de forças na vertical:
VA+ VB-40-10=0
VA+VB=50KN
Somatória de momentos:
10*2-5-40*1+VB*2-40=0
20-5-40-40+VB*2=0
VB=(-20+5+40+40)/2
VB=32,5KN
VA=50-VB
VA=50-32,5
VA=17,5KN
CALCULOS
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