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Calculo 2

Por:   •  31/3/2015  •  Trabalho acadêmico  •  1.329 Palavras (6 Páginas)  •  251 Visualizações

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FACULDADE ANHANGUERA

Trabalho de Calculo 2

3° Período de Engenharia Mecânica

Felipe J. Ribeiro Guerra

06/03/2015


01. Encontre a equação da reta tangente que toca ponto indicado para a função:

a) 𝑦 = 9 − 𝑥 ² ; 𝑃(−3, 0)

Y = f(x) = 9 – x²  

F(x₁ + ∆x) = 9 – (x₁ + ∆x)²

F(x₁ + ∆x) = 9 – [(x₁ ²+2x₁∆x +(∆x )²]

F(x₁ + ∆x) = 9 – x₁ ² – 2x₁∆x  – (∆x )²
[pic 1]

[pic 2]

[pic 3]

[pic 4]

[pic 5]

  [pic 6][pic 7][pic 8][pic 9]

[pic 10]

y₂ - y₁  =  [pic 11]

y₂  0  =   6[[pic 12][pic 13]

y₂   = 6[pic 14]

y₂   =   6[pic 15]

y = 6x + 18

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b)  𝑦 = 𝑥³  + 1; 𝑃(−2, -7)

Y = f(x) = 𝑥³  + 1

F(x₁ + ∆x) = (x₁ + ∆x)³ +1

F(x₁ + ∆x) = (-2 + ∆x)³ +1

F(x₁ + ∆x) = -2³ + 3(-2)²∆x + 3(-2)(∆x)² + (∆x)³ +1

F(x₁ + ∆x) = -7 + 12∆x - 6(∆x)² + (∆x)³

[pic 16]

[pic 17]

[pic 18]

[pic 19]

[pic 20]

[pic 21]

[pic 22]

[pic 23]

y₂ - y₁  =  [pic 24]

y₂ + 7  =  [pic 25]

y₂   =   - 7[pic 26]

y   =  [pic 27]

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c)  y =;   𝑄(3, 2)[pic 28]

y = f(x) =;   [pic 29]

F(x₁ + ∆x) = [pic 30]

[pic 31]

[pic 32]

[pic 33]

[pic 34]

[pic 35]

[pic 36]

[pic 37]

[pic 38]

[pic 39]

y₂ - y₁  =  [pic 40]

y₂ - 2  =  [pic 41]

y₂   =  [pic 42]

y₂   =  [pic 43]

y₂   =  [pic 44]

y   =  [pic 45]

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d)  ;  P(2,1)[pic 46]

[pic 47]

[pic 48]

[pic 49]

[pic 50]

[pic 51]

[pic 52]

[pic 53]

[pic 54]

[pic 55]

[pic 56]

[pic 57]

[pic 58]

[pic 59]

[pic 60]

[pic 61]

[pic 62]

[pic 63]

y₂ - y₁  =  [pic 64]

y₂ - 1  =  [pic 65]

y₂ =  [pic 66]

y₂ =  [pic 67]

y =  [pic 68]

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e)  ;  P(3, )[pic 69][pic 70]

[pic 71]

[pic 72]

[pic 73]

[pic 74]

[pic 75]

[pic 76]

[pic 77]

[pic 78]

[pic 79]

[pic 80]

[pic 81]

y₂ - y₁  =  [pic 82]

y₂ -   =  [pic 83][pic 84]

y₂ -   =  [pic 85][pic 86]

y₂ =   + [pic 87][pic 88]

y₂ = [pic 89]

y₂ =[pic 90]

y =[pic 91]

______________________________________________________________________________________________________

f) y = 3x² - 2x + 5:; P(-1, 10)

F(x₁ + ∆x) =3(-1+∆x)² - 2(-1 +∆x) + 5

F(x₁ + ∆x) =3[(-1)²+ 2(-1)(∆x)+(∆x)² ] +2 - 2∆x  + 5

F(x₁ + ∆x) =3 - 6∆x + (∆x)² +7 - 2∆x  

F(x₁ + ∆x) =10 - 8∆x + (∆x)²

[pic 92]

[pic 93]

[pic 94]

[pic 95]

[pic 96]

[pic 97]

y₂ - y₁  =  [pic 98]

y₂ - 10  =  [pic 99]

y₂ - 10  =  [pic 100]

y₂   =   + 10[pic 101]

y₂   =  [pic 102]

y =  [pic 103]

______________________________________________________________________________________________________

g) y = x³ - 8; P(0, -8)

F(x₁ + ∆x) = (x₁ + ∆x)³ - 8

F(x₁ + ∆x) = x₁³ + 3 x₁²∆x + 3 x₁(∆x)²  +  (∆x)³ - 8

F(x₁ + ∆x) = 0³ + 3(0)²∆x + 3 (0)(∆x)²  +  (∆x)³ - 8

F(x₁ + ∆x) =  (∆x)³ - 8

[pic 104]

[pic 105]

[pic 106]

[pic 107]

[pic 108]

[pic 109]

y₂ - y₁  =  [pic 110]

y₂ + 8  =  [pic 111]

y₂  = - 8

y   = - 8

______________________________________________________________________________________________________

h)  ; P (1, 2)[pic 112]

[pic 113]

[pic 114]

[pic 115]

[pic 116]

[pic 117]

[pic 118]

[pic 119]

[pic 120]

[pic 121]

[pic 122]

[pic 123]

[pic 124]

[pic 125]

[pic 126]

[pic 127]

y₂ - y₁  =  [pic 128]

y₂ - 2  =  [pic 129]

y₂ =  [pic 130]

y₂ =  [pic 131]

y=  [pic 132]

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; P(-2, -)[pic 133][pic 134]

[pic 135]

[pic 136]

[pic 137]

[pic 138]

[pic 139]

[pic 140]

[pic 141]

[pic 142]

[pic 143]

[pic 144]

[pic 145]

[pic 146]

[pic 147]

y₂ - y₁  =  [pic 148]

y₂ -(-  ) =  [pic 149][pic 150]

y₂ +   =  [pic 151][pic 152]

y₂   =    -  [pic 153][pic 154]

y₂   =    -  [pic 155][pic 156]

y₂   =  [pic 157]

y  =  [pic 158]

...

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